svd and real representation of quaternionsgreenspun.com : LUSENET : quaternions : One Thread
hello, my problem is that i'm using the real representation of quaternions to compute SVDQ but i really do not manage to get back the singular vector with it. do you have any idea about that? benoit PS thanks to cayley dickinson i can have back the singular vectors
-- benoit roue (firstname.lastname@example.org), May 13, 2003
When I work with quaternions, every number or matrix is a quaternion, so the expression:
A . X = B
is composed of three quaternions (this is not the general situation, but the one I work with). If one wants to determine X, then multiply on the left by the inverse of A. The inverse of A is easy to calculate: it is the transpose of A divided by its norm, so:
X = Transpose(A) . B/norm(A)
X will have the matrix form of a quaternion, not a singular vector.
-- Doug Sweetser (email@example.com), May 13, 2003.